106 lines
2.6 KiB
JavaScript
106 lines
2.6 KiB
JavaScript
// let commonURL = "http://192.168.50.115:8081";
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let commonURL = "/api";
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// 设置后台服务地址
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axios.defaults.baseURL = commonURL;
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axios.defaults.timeout = 2000;
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// request拦截器，将用户token放入头中
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let token = sessionStorage.getItem("token");
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axios.interceptors.request.use(
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config => {
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if(token) config.headers['authorization'] = token
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return config
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},
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error => {
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console.log(error)
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return Promise.reject(error)
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}
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)
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axios.interceptors.response.use(function (response) {
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// 判断执行结果
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if (!response.data.success) {
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return Promise.reject(response.data.errorMsg)
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}
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return response.data;
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}, function (error) {
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// 一般是服务端异常或者网络异常
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console.log(error)
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if(error.response.status == 401){
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// 未登录，跳转
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setTimeout(() => {
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location.href = "/login.html"
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}, 200);
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return Promise.reject("请先登录");
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}
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return Promise.reject("服务器异常");
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});
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axios.defaults.paramsSerializer = function(params) {
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let p = "";
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Object.keys(params).forEach(k => {
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if(params[k]){
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p = p + "&" + k + "=" + params[k]
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}
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})
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return p;
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}
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const util = {
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commonURL,
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getUrlParam(name) {
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let reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");
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let r = window.location.search.substr(1).match(reg);
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if (r != null) {
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return decodeURI(r[2]);
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}
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return "";
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},
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formatPrice(val) {
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if (typeof val === 'string') {
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if (isNaN(val)) {
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return null;
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}
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// 价格转为整数
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const index = val.lastIndexOf(".");
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let p = "";
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if (index < 0) {
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// 无小数
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p = val + "00";
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} else if (index === p.length - 2) {
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// 1位小数
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p = val.replace("\.", "") + "0";
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} else {
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// 2位小数
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p = val.replace("\.", "")
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}
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return parseInt(p);
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} else if (typeof val === 'number') {
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if (!val) {
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return null;
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}
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const s = val + '';
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if (s.length === 0) {
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return "0.00";
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}
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if (s.length === 1) {
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return "0.0" + val;
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}
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if (s.length === 2) {
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return "0." + val;
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}
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const i = s.indexOf(".");
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if (i < 0) {
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return s.substring(0, s.length - 2) + "." + s.substring(s.length - 2)
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}
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const num = s.substring(0, i) + s.substring(i + 1);
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if (i === 1) {
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// 1位整数
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return "0.0" + num;
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}
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if (i === 2) {
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return "0." + num;
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}
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if (i > 2) {
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return num.substring(0, i - 2) + "." + num.substring(i - 2)
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}
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}
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}
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}
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